---16t^2+160t+300=5000

Solution for ---16t^2+160t+300=5000 equation:

---16t^2+160t+300=5000

We move all terms to the left:

---16t^2+160t+300-(5000)=0

determiningTheFunctionDomain
-16t^2+160t+300-5000--=0

We add all the numbers together, and all the variables

-16t^2+160t=0

a = -16; b = 160; c = 0;
Δ = b2-4ac
Δ = 1602-4·(-16)·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-160}{2*-16}=\frac{-320}{-32}
=+10
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+160}{2*-16}=\frac{0}{-32}
=0
$